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# Spiral calculator

This online calculator computes unknown archimedean spiral dimensions from known dimensions. The spiral dimensions include: outer diameter, inner diameter, separation distance (distance between arms, thickness), spiral length, number of turnings

This is an universal calculator for the Archimedean spiral.

We have five spiral dimensions: outer diameter - D, inner diameter - d, thickness or separation distance or distance between arms - t, spiral length - L, number of turnings - n. These dimensions are related (see formulas below the calculator), and you can calculate any two, if you know the other three.

We can see spirals in everyday life in any objects, that are in rolled form: rolls of paper, tapes, films, and so on. You can easily find out some of the dimensions of these objects, like diameters and thickness, or number of turnings, and, using the calculator below, calculate the missing ones. For example, you can calculate roll length from inner and outer diameters and roll thickness, or number of turnings. You can also solve inverse problem (when you know the roll length) - calculate thickness and number of turnings using roll length and both diameters. Some theory and formulas, as usual, can be found below the calculator.

Please be careful with units control, when you enter the known dimensions! 20 meters are not the same as 20 millimeters...

#### Spiral calculator

Digits after the decimal point: 4
Spiral length

Inner diameter

Outer diameter

Thickness

Number of turnings

### Archimedean spiral

The Archimedean spiral (also known as the arithmetic spiral) is a spiral corresponding to the locations over time of a point M moving away from a center point O with a constant speed along a line OA that rotates around the center point O with constant angular velocity.

If we denote the distance from O to M as ρ, and rotation angle as φ, then we can describe a spiral with polar equation:

$\rho = k \phi$,

where k is size parameter, which equals to change of distance when angle is rotated by 1 radian. After one turn (an angle increases by ) the distance increases by 2πk.

$a = 2 \pi k$

This increase is the distance between two arms of a spiral, or separation distance, or thickness of a spiral. We can rewrite our initial equation using a:

$\rho = \frac{a}{2 \pi} \phi$

Since thickness is constant, the more the point M moves away from center, the more the spiral resembles the circle.

To derive the formula for the spiral length, we will examine infinitesimal length change.

An infinitesimal spiral segment dl can be thought of as hypotenuse of the dl, and dh triangle. Hence:

$dl = \sqrt{d\rho^2+dh^2}$

An infinitesimal spiral segment dh can be replaced with an infinitesimal segment of a circle with radius ρ, hence its length is ρdφ.

$dl = \sqrt{d\rho^2+\rho^2d\phi^2}$

Using polar equation of a spiral we can replace ρ with , and with kdφ

$dl = \sqrt{k^2d\phi^2+k^2\phi^2d\phi^2}=kd\phi\sqrt{1+\phi^2}=\frac{a}{2\pi}\sqrt{1+\phi^2}d\phi$

Now the have the dependance of the length dl on the angle . To find out the length, we need to integrate from the initial angle to the final angle.

$L=\int \limits _{\phi_0}^{\phi_1}\frac{a}{2\pi}{\sqrt {1+\phi ^{2}}}d\phi$

Long story short, the final integral is:

$L=\frac{a}{2\pi}\left( \frac{\phi_1}{2}\sqrt{\phi_1^2+1}+\frac{1}{2}ln(\phi_1+\sqrt{\phi_1^2+1}) - \frac{\phi_0}{2}\sqrt{\phi_0^2+1}-\frac{1}{2}ln(\phi_0+\sqrt{\phi_0^2+1}) \right)$

If a spiral starts from zero angle (from the center), the formula is simplified:

$L=\frac{a}{2\pi}\left( \frac{\phi_1}{2}\sqrt{\phi_1^2+1}+\frac{1}{2}ln(\phi_1+\sqrt{\phi_1^2+1}) \right)$

But in real life, of course, roll of material does not start from the center. Usually it has sleeve, hence inner diameter and initial angle. How all these parameters are related?

Here is how number of turns n is related to angles:

$n = \frac{\phi_1-\phi_0}{2\pi}$

And here is how diameters are related to angles (this follows directly from the spiral polar equation)

$D = \frac{a}{\pi}\phi_1 \\ d = \frac{a}{\pi}\phi_0$

This is all formulas that we need to find out unknown dimensions by known dimensions. However, note that the length equation is transcendental and the solution of inverse task (finding unknown dimensions while the length is among the known dimensions) requires numerical methods. This calculator uses Secant method.

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PLANETCALC, Spiral calculator